Correct Answer - A
Time period of a revolution of a planet,
`T=(2pir)/r=(2pir)/(sqrt((GM_(S))/r))=(2pir^(3//2))/(sqrt(GM_(S))`
Where `M_(S)` is the mass of the sun. Squaring both sides, we get
`T_(2)=(4pi^(2)r^(3))/(GM_(S))`
The graphs between `T_(2) and r_(3)` is a straight line whose slope is `(4pi^(2))/(GM_(S))`