Question

For particles of equal masses M that move along a circle of radius R under the action of their mutual gravitational attraction. Find the speed of each particle.

Answer 1

in this case, the particles maintain gravitational force of attraction diametrically. The gravitational force one of the particles must be equal to the necessary centripetal force
`(mV^(2))/r=(Gmm)/((2r)^(2))rArr V=sqrt((Gm)/(4r))`