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+1 vote
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in Physics by (85.7k points)
closed
`30 kg` ice at `0^@C` and `20 g` of steam at `100^@C` are mixed. The composition of the resultant mixture is
A. `40 g` of water and `10 g` steam at `100^@C`
B. `10g` of ice and `40 g` of water at `0^@C`
C. `50g` of water at `100^@C`
D. `35 g` of water and `15 g` of steam at `100^@ C`

1 Answer

+1 vote
by (90.5k points)
 
Best answer
Correct Answer - A
`m_(s)L_(s) =(m_(ice)L_(ice) + m_(ice) s Delta theta)`
Where `m_(s)` = mass f steam condensed to rise temperature of ice to `100^@C` water.

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