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The angular speed of earth is `"rad s"^(-1)`, so that the object on equator may appear weightless, is (radius of earth = 6400 km)
A. `1.23 xx 10^(-3)`
B. `6.20 xx 10^(-3)`
C. `1.56`
D. `1.23 xx 10^(-5)`

1 Answer

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by (67.7k points)
 
Best answer
Correct Answer - A
At equator, `g=g-R omega^(2)rArr 0=g-Romega^(2)`
`:. omega=sqrt((g)/(R))=sqrt((9.8)/(6400xx10^(3)))=1.23xx10^(-3) "rad s"^(-1)`.

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