Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
145 views
in Physics by (85.7k points)
closed
The molar heat capacity of a gas at constant volume is found to be `5 cal mol^(-1) K^(-1)`. Find the ratio`gamma = C_p/C_v` for the gas. The gas constant `R=2 cal mol^(-1) K^(-1).

1 Answer

0 votes
by (90.5k points)
 
Best answer
We have `C_v = 5 cal mol^(-1) K^(-1).
Thus. `C_p = C_v + R = 5 cal mol^(-1) K^(-1) + cal mol^(-1) = 7 cal mol^(-1) K^(-1)`
or, C_p / C_v = 7/5 = 1.4`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...