Question

A bomber moving horizontally with `500m//s` drops a bomb which strikes ground in 10s. The angle of strike with horizontal is
A. `tan^(-1) ((1)/(5))`
B. `60^(@)`
C. `45^(@)`
D. `tan^(-1)(5)`

Answer 1

Correct Answer - A
Horizontal component of velocity `v_(x) = 500 ms^(-1)` and vertical component of velocity while striking the ground can be given as
`v_(y) = 0 + 10 xx 10 = 100 ms^(-1)`
`:.` Angle with which it strikes the ground
`theta = tan^(-1) ((v_(y))/(y_(x))) = tan^(-1) ((100)/(500)) = tan^(-1)((1)/(5))`