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Two forces are such that the sum of their magnitudes is 18N and their resultant is 12 N which is perpendicular to the smaller force. Then the magnitude of the forces are
A. (a) 12N, 6N
B. (b) 13N, 5N
C. (c) 10N, 8N
D. (d) 16N, 2N

1 Answer

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Correct Answer - B
Let the two forces be `F_1` and `F_2` and let `F_2ltF_1`. R is the resultant force.
Given `F_1+F_2=18` …(i)
From the figure `F_2^2+R^2=F_1^2`
`F_1^2-F_2^2=R^2`
`:.` `F_1^2-F_2^2=144`
Only option (b) follows equation (i) and (ii).
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