Here, ` r = 1 m , omega = 4 rad s^(-1),mu = 0.2`
The wooden block will continue to revolve with the table till force of friction is greater than or atleast equal to centripetal force required by it i.e,
`F ge mr omega^(2)` or `muR ge mr omega^(2)` or m`u ge mr omega^(2) `
` (mug)/(omega^(2) l)ge r or r le(mug)/(omega^(2)) i. e r le(0.2 xx 9.8)/(4)^(2)`
`r le 0. 123 m` or `r le 12 .3 cm`
`:.` The block placed at 10 cm will revolve with the table.