Correct Answer - B::D
`omega = 3rad//s`
`A = 0.2m`
At `x = 5cm`
`v = +-omegasqrt(A^(2) - x^(2))`
`= +- 3.0sqrt((0.2)^(2) - (0.05)^(2))`
`= +- 0.58m//s`
`a = - omega^(2)x = - (3)^(2)(0.05)`
` = - 0.45m//s`
At `x = 0`
`v = +-omega A`
`= +- (3.0)(0.2)`
`= +- 0.6 m//s`
`a = - omega^(2)x = - (3)^(2)(0)`
`= 0`