Question

A suitcase is gently dropped on a conveyor belt moving at `3ms^(-1)` If the coefficient of friction between the belt and suitcase is `0.5` how far will the suitcase move on the belt before coming to rest ?

Answer 1

Correct Answer - `0.92m`
Here, `u = 3ms^(-1), mu = 0.5, s=? upsilon = 0`
`a = - mu g = - 0.5 xx 9.8 = - 4.9 m//s^(2)`
From `upsilon^(2) - u^(2) = 2` as
`s = (upsilon^(2) - u^(2))/(2a) = (0 -3^(2))/(2 (-4.9)) = 0.92 m`.