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An elavator is going up vertically with a constant accelerartion of `2m//s^(2)`. At the instant when its velocity is `4m//s` a ball is projected from the floor of the elavator with a speed of `4m//s` relative to the floor with an angular eleavation of `60^(@)`. The time taken by the ball to return the floor is `(g=10m//s^(2))`
A. `1/3s`
B. `1/(sqrt(3))s`
C. `2/(sqrt(3))s`
D. `sqrt(3)s`

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