Correct Answer - D
(d) The acceleration of the centre of mass of cylinder rolling
down an inclined plane is
`a_c = (g sin theta)/(I_P)/(1+MR^2)`
Here `I_Pgt I_Q` because in
case of P the mass is
concentrated away from
the axis. `:. a_P lt a_Q rArr v_p lt v_Q rArr omega_p lt omega_Q`