Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
84 views
in Physics by (84.4k points)
closed by
The surface density (mass/area) of a circular disc of radius a depends on the distance from the centre as `rho(r)=A+Br.` Find its moment of inertia about the line perpendicular to the plane of the disc through its centre.
A. `pia^(2)(A/2 + (2a)/5)`B
B. `pia^(4)(A/2 + (2B)/5)`
C. `2pia^(3)(A/2+ (Ba)/5)`
D. None of these

1 Answer

0 votes
by (82.1k points)
selected by
 
Best answer
a) dm = `2pirdr(rho)` = (A+Br)(2pirdr)`
`I = int_(0)^(a)dmr^(2)` = `(piAa^(4))/2+ (2piBa^(5))/5 = pia^(4)(A/2+(2a)/5B)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...