# A stick AB of mass M is tied at one end to a light string OA. A horizontal force F = Mg is applied at end B of the stick and its remains in equilibr

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A stick AB of mass M is tied at one end to a light string OA. A horizontal force F = Mg is applied at end B of the stick and its remains in equilibrium in position shown. Calculate angles alpha and beta.

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Correct Answer - alpha = tan^(-1) (2); beta = 45^(@)