Correct Answer - A::B
Power `=(1)/(2)rhoomega^(2)A^(2)Sv`
But, `rhoS = mu`
and `v=sqrt((T)/(mu))`
`:. rhoSv=sqrt(muT)`
Hence, power `=(1)/(2)(2pif)^(2)A^(2) sqrt(Tmu)`
`2pi^(2) f^(2) A^(2) sqrt(Tmu)`
`=(2) (pi)^(2)(60)^(2) (0.06)^2sqrt(80 xx 5 xx 10^(-2)`
`=512W`