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If one mole of a monatomic gas `(gamma=5/3)` is mixed with one mole of a diatomic gas `(gamma=7/5),` the value of gamma for mixture is
A. `1.40`
B. `1.50`
C. `1.53`
D. `3.07`

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Correct Answer - B
(b) `(n_1+n_2)/(gamma-1)=(n_1)/(gamma_1-1)+(n_2)/(gamma_2-1)`
Here, `n_1=n_2=1, gamma_1=2/5, gamma_2=5/3`

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