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Two moles of helium gas are taken over the cycle ABCDA, as shown in the P-T diagram
image
The net work done on the gas in the cycle ABCDA is :
A. `276R`
B. `1076R`
C. `1904R`
D. zero

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Correct Answer - A
(a) The net work in the cycle ABCDA is
`W=W_(AB)+W_(BC)+W_(CD)+W_(DA)`
`=400R+2.303nRTlog(P_B)/(P_C)+(-400R)-414R`
`=2.303xx2Rxx500log(2xx10^5)/(1xx10^5)-414R`
`=693.2R-414R=279.2R`

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