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From athe velocity time graph, given in of a particle moving in a straight line, one can conclude that
image.
A. Its average velocity during the `12 s` interval is `24//7 m s^(-1)`.
B. Its velocity for the first `3 s` is uniform and is eual to `4 m s^(-1)`.
C. The body has a constant acceleration between `t=3 s` and `t=8 s`.
D. The body has a uniform retardation from `t=8 s` to `t=12 s`.

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Correct Answer - D
Displacemeant in `12 s ` =Area undr `v-t` groph
`=(1)/(2) xx (12+5) 4=34 m`
`V_(av) =(Desplacement )/(Time ) =(34)/(12) =(17)/(6) m s^(-1)`
Hence, (a) is incorrect, (b) is incorrect because during first `3 s`, velocity increases from= to `4 m s^(-1)` option, (c ) is incorrect, because in part `AB` velocity is constant.

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