Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
5.0k views
in Physics by (76.0k points)
closed by
a. A `2-kg` situated on a smooth fixed incline is connected to a spring of negligible mass, with spring constant `k=100Nm^-1`, via a frictionless pulley. The block is released from rest when the spring is unstretched. How far does the block moves down the incline before coming (momentarily) to rest? What is its acceleration at its lower point?
image
b. The experiment is repeated on a rough incline. If the block is observed to move `0.20m` down along the incline before it comes to instantaneous rest, calculate the coefficient of kinetic friction.

1 Answer

0 votes
by (87.4k points)
selected by
 
Best answer
Correct Answer - a. `24m`; `6ms^-2`, b. `1/8`
(a) At the extreme position blocks stops.
Applying work-energy theorem, we get
`mg sin 37^@=1/2ks^2`
`2xx10xxsxx3/5=1/2xx100xxs^2`
On solving `s=0.24m`
Acceleration at its lowest point, `a=(ks-mg sin 37^@)/(m)`
`=(100xx0.24-2xx10xx3/5)/(2)=6ms^-2`
(b) `W_g+W_(f riction)+W_(spri ng)=DeltaKE`
`mg sin 37^@+mumgcos37^@xxs=1/2ks^2`
`mgsin37^@-1/2ks=mumgcos 37^@`
`2xx10xx3/5-1/2xx100xxs=muxx2xx10xx4/5`
Gives `s=0.020m`
`mu=(12-50s)/(16)impliesmu=1/8`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...