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In the arrangement shown in figure match the following
image
`{:("column1","column2"),("A Velocities of center of mass","P 2SI unit"),("B Velocity of combined mass when compression in the spring is maximum","1 SI unit"),("C Maximum compression in the spring","4 SIunit"),("D Maximum potential energy stored in the spring","0.5SI unit"):}`

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Best answer
Correct Answer - A `rightarrow`q, B `rightarrow`q, C`rightarrow`q, D `rightarrow`p
`v_(CM)=(m_(1)v_(1) + m_(2)v_(2)) = 1ms^(-1)`
During maximum compression also, velocity of combined mass is `ms^(-1)`.
Now, `U_(max) = K_(1) - K_(2)`
`1/2KX_(max)^(2) = 2J`
We have, `X_(max) = 1m`

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