Correct Answer - A `rightarrow`q, B `rightarrow`q, C`rightarrow`q, D `rightarrow`p
`v_(CM)=(m_(1)v_(1) + m_(2)v_(2)) = 1ms^(-1)`
During maximum compression also, velocity of combined mass is `ms^(-1)`.
Now, `U_(max) = K_(1) - K_(2)`
`1/2KX_(max)^(2) = 2J`
We have, `X_(max) = 1m`