Question

The angular velocity of a particle moving in a circle of radius `50 cm` is increased in 5 min from `100` revolutions per minute to `400` revolutions per minute. Find the tangential acceleration of the particle.

Answer 1

` v_1 = 100//60 ros, v-2 = 400//60 rps`
Angular acceleration,
` alpha= (omega-2-omega_1)/t = (2 pi v-2 -2 pi v-1)/t`
linear acceleration, `a =r alpha`.