Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
109 views
in Physics by (82.2k points)
closed by
Calculate the centripetal acceleation of a point on the equator of earth due to the rotatin of earth about its wn axis . Radius of earth ` = 6400 km`.

1 Answer

0 votes
by (84.4k points)
selected by
 
Best answer
Centripetal acceleration, `a-c = R 4 pi^2 //T^2`
Here, `R= 6400 km and T= 24 hours. So
` a_c = (6400 xx (22/7)^2)/((24))^2 = 439 km h^(-2)`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...