Correct Answer - C
Here ` r= 100 m, t= 62 sec`. As in one complete circular motion, car comes back to its starting point. So net displacement =0 and hence, bet velocity =0`.
Total path coverd in ` 62.8 sec = 2 pi r`
`=92 xx 3.14 xx 100 ) m = 628 m`
:. Average speed ` = ( 628)/(62.8) = 10 m//a.