Correct Answer - A
As net velocity of contact point is not zero, the disc rolls with slipping as `omega` about `IC` is the same
`omega=(v_(0))/(IO)=(v_(c))/(IC)`
`2/x=4/(x+R)` or `x=0.2m`
Velocity of `P` is given by `v_(p)=(IP)omega=sqrt(5)Rxx2/x=2sqrt(5)m//s`