Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
198 views
in Physics by (76.0k points)
closed by
A disc of radius `20 CM` is rolling with slipping on a flat horizontal surface. At a certain instant the velocity of its centre is `4 m//s` and its angular velocity is `10 rad//s`. The lowest contact point is `O`.
image
Velocity of point `O` is
A. `2m//s`
B. `4m//s`
C. `1m//s`
D. `3m//s`

1 Answer

0 votes
by (87.4k points)
selected by
 
Best answer
Correct Answer - A
As net velocity of contact point is not zero, the disc rolls with slipping as `omega` about `IC` is the same
image
`omega=(v_(0))/(IO)=(v_(c))/(IC)`
`2/x=4/(x+R)` or `x=0.2m`
Velocity of `P` is given by `v_(p)=(IP)omega=sqrt(5)Rxx2/x=2sqrt(5)m//s`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...