Correct Answer - `1.01146xx10^(5)`
Excess pressure `=2T//r=146Pa`
Pressure `h` below the surface `rho_(0)+rhog`
`:. P=(P_(0)+rhogh)+2T//r`
`=1xx10^(5)+10^(3)xx10xx0.1`
`+2xx(7.3xx10^(-2))/10^3`
`=1xx10^(5)+10^(3)+146`
`=1xx10^(5)+1146`
`=1.01146xx10^(5)`
