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Air is pushed inot a soap bubble of radius r to duble its radius. If the surface tension of the soap solution is S, the work done in the process is
A. `2piD^(2)T`
B. `4piD^(2)T`
C. `6piD^(2)T`
D. `8piD^(2)T`

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Correct Answer - C
Work done`=`(increase in surface)`xx`Surface tension
`=2xx[4pi((2D)/2)^(2)-4pi(D/2)^(2)]xxT`
(since for sap bubble, there are two free surfaces)
`=2xx(4piD^(2)=piD^(2))T=6piD^(2)T`

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