Question

An object moving with uniform acceleration has a velocity of `12.0 cm//s` in the positive `x` direction when its `x` corrdinate is `3.00 cm`. If its `x` coordinate `2.00s` later is `-5.00cm`, what is its acceleration?

Answer 1

Correct Answer - `-16 cm//s^(2)`
`x = x_(0) +ut +(1)/(2)a t^(2) rArr - 5 = 3 +12 xx 2 +(1)/(2) a xx 2^(2)`
`- 5 = 27 +2a rArr a =- 16 m//s^(2)`