Question

The fig. shows the `v-t` graph of a particle moving in straight line. Find the time when particle returns to the starting point.

Answer 1

Correct Answer - `36.2sec`.
For particle to return to origin. Net displacement is zero.
`0 = (1)/(2) xx 25 xx 25 +(1)/(2) xx (-4) xx (t - 25)^(2)`
`2(t -25)^(2) = 125`
`t - 25 = +- 11.2`
`t = 36.2sec.`