Correct Answer - D
Frequency heard by the observes will be maxmum when the source is in position D. In this case, source will be approaching towards the stationary observer, almost along the line of sight (as observer is stationed at a larger distance.)
`n_(max)=(v)/(v-v_S)n`
`=(330xx440)/(330-1.5xx20)`
`=484Hz`
Similarly, frequency heard by the observer will be minimum when the source reaches at position B. Now, the source will be moving away from the observer.
`n_(min)=(v)/(v+v_S)xxn=(330)/(330+1.5xx20)xx440`
`=(330xx440)/(360)=403.3Hz`