Correct Answer - D
Initially wall behaves as an approaching observer, so frequency of sound reaching the wall is
`n_1=(c+v)/(c )n`
while reflecting, the wall behaves as an approaching source, so frequency received by stationary observer is
`n_2=(c)/(c-v)n_1=(c)/(c-v)xx(c+v)/(c)n=(c+v)/(c-v)n`
Direct frequency received by observer in n. the number of beats is
`x=n_2-n=(c+v)/(c-v)n-n=(2nv)/(c-v)`