Correct Answer - B
As the rod is heated, it expands. No external torque is acting on the system so angular momentum should be conserved.
L = Angular momentum - `I omega` = constant
`rArr I_(1)omega_(1) = I_(2) omega_(2)` ltbr. Due to expansion of the rod `I_(2) gt I_(1)`
`rArr (omega_(2))/(omega_(1)) = (I_(1))/(I_(2)) lt 1`
`rArr omega_(2) lt omega_(1)`
So, angular velocity (speed of rotation) decreases.
