Question

For the stationary wave `y=4sin((pix)/(15))cos(96pit)`, the distance between a node and the next antinode is
A. `7.5`
B. `15`
C. `22.5`
D. `30`

Answer 1

Correct Answer - A
Comparing given equation with standard equation
`y=2asin.(2pix)/(lamda)cos.(2pivt)/(lamda)` gives us
`(2pi)/(lamda)=(pi)/(15)implieslamda=30`
distance between nearest node and antinodes
`=(lamda)/(4)=(30)/(4)=7.5`.