Question

A string is rigidly tied at two ends and its equation of vibration is given by `y=sin2pix.cos2pit`. Then minimum length of string is
A. `1 m`
B. `1/2`m
C. `5m`
D. `2pim`

Answer 1

Correct Answer - B
Given equation of stationary wave is `y=sin2pixcos2pit`, comparing it with standard equation.
`y=2Asin.(2pix)/(lamda)cos.(2pit)/(T)`
We have `(2pix)/(lamda)=2piximplieslamda=1m`
Minimum distance of string (first mode)
`I_(min)=(lamda)/(2)=(1)/(2)m`