Two identical sound `S_1` and `S_2` reach at a point P is phase. The resultant loudness at point P is `n` dB higher than the lou

Correct Answer - D
Let `a` be the amplitude due to `S_1` and `S_2` individually.
Loudness due to `S_1=I_1=Ka^2`
Loudness due to `S_(1)+S_(2)=I=K(2a)^(2)=4I_(I)`
`:. n=10log_(10)((4l_1)/(l_1))`
`=10log_(10)(4)=6`

Two identical sound `S_1` and `S_2` reach at a point P is phase. The resultant loudness at point P is `n` dB higher than the loudness of `S_1` the val

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