Correct Answer - D
For second overtone (3rd harmonic) in open organ pipe,
`(3lamda)/(2)=l_0implieslamda=(2l_0)/(3)`
For first overtone (3rd harmonic) in closed organ pipe,
`(3lamda)/(4)=l_Cimplieslamda=(4l_C)/(3)=(4L)/(3)`
so, `(2l_0)/(3)=(4L)/(3)impliesl_0=2L`