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The velocity of sound waves in air is `330m//s`. For a particluar sound in air, a path difference of `40 cm` is equivalent to a phase difference of `1.6pi`. The frequency of this wave is
A. `165 hz`
B. `150 Hz`
C. `660 Hz`
D. `330 Hz`

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Correct Answer - C
Phase difference `=(2pi)/(lamda)xx` Path difference
`implies=1.6pi=(2pi)/(lamda)xx40implieslamda=50cm=0.5m`
`impliesv=nlamdaimplies330=0.5xxnimpliesn=660Hz`

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