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Heat generated in a circuit is given by `H = I^2` Rt. If error in measuring current I, resistance R and time t are 2%, 1% and 3% respectively, then percentage error in calculating heat is :

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Correct Answer - 8
As `H = I^2 Rt`
`:. (DeltaH)/(H) = 2((Delta I)/(I)) + (Delta R)/(R ) +(Delta t)/(t)`
`= 2xx 2% + 1% + 3% = 8%`

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