Here, `m=1800kg`
frictional force, `f=4000N,`
uniform speed, `v=2.0m//s`
Downward force on elevator is
`F=mg+f=1800xx10+4000=22000N`
The motor must supply enough power to balance this force. As
`P=Fxxv`
`:. P=22000xx2=44000wat t`
`P=(44000)/(746)h.p. =59 h.p.`