Question

A monkey of mass `20kg` is holding a vertical rope. The rope will not break when a mass of `25kg` is suspended from it but will break it the mass exeeds `25kg` . What is the maximum acceleration with which the monkey can climb up along the rope? `(g=10m//s^(2))` .
A. `2.5m//s^(2)`
B. `5m//s^(2)`
C. `7m//s^(2)`
D. `10m//s^(2)`

Answer 1

Correct Answer - A
Maximum tension in rope.
Equation of motion of monkey.
`T-mg=ma`
`250-20xx10=20xxa` implies `a=2.5m//s^(2)` .