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The temperature at which the root mean square velocity of the gas molecules would becomes twice of its value at `0^(@)C` is

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The temperature at which the root mean square velocity of the gas molecules would becomes twice of its value at `0^(@)C` is
A. `819^(@)C`
B. `1092^(@)C`
C. `1100^(@)C`
D. `1400^(@)C`
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Correct Answer - A
`(C_t)/(C_0) = sqrt((273+t)/(273))`
or `4 xx 273 - 273 = t`
or `t = 3 xx 273 = 819^(@)C`.
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