Question

When `1 kg` of ice at `0^(@)C` melts to water at `0^(@)C`, the resulting change in its entropy, taking latent heat of ice to be `80 cal//g` is
A. `8xx10^(4)cal//K`
B. `80cal//K`
C. `293 cal//K`
D. `273 cal//K`

Answer 1

Correct Answer - C
change in entropy
`DeltaS = (ml)/(T) = (1000xx80)/(273)=293 cal K^(-1)`.