Correct Answer - C
( c) From law of conservation of angular momentum if no external torque is acting upon a body rotating about an axis, then the angular momentum of the body remains constant that is
`J = I omega = constant`
Hence, if decreases, `omega` increases and vice-versa. When liquid is dropped, mass increase hence `I` increases `(I = mr^2)` So, `omega` decreases, but as soon as the liquid starts falling `omega` increases again.