Relation between Kelvin scale and Celsius scales is `T_(C)=T_(K) = 273.15`
Where `T_(C), T_(K)` = temperature on Celsius and Kelvin scales respectively.
For Neon `T_(C) = 24.57-273.15 = -248.58^(@)C`
For `C_(O_2)` `T_(C) = 216.55-273.15 = -56.60^(@)C`
Relation between Kelvin and Farenheight scalse is, `(T_(F)-32)/(180) = (T_(K)-273.15)/(100)`
`T_(F) = (180)/(100) (T_(K)-273.15)+32`
For Neon, `T_(F)=(180)/(100)(42.57-273.15)+32 = -415.44^(@)F`
For `C_(O_2)` `T_(F) = (180)/(100)(216.55-273.15)+32 = -69.88^(@)F`.