Question

Find the equation of the line whose slope is − 4/3 and which passes through (−3, 4)

Answer 1

Given, slope =  − 4/3

The equation passes through (−3, 4) = (x₁, y₁)

Substituting the values in y - y₁ = m (x − x₁), we get,

y − 4 = (-4/3)(x + 3)

3y − 12 = −4x − 12

4x + 3y = 0, which is the required equation.