Total cross-sectional area of the femurs is `A=2xx10cm^(2)=20xx10^(-4)m^(2)`. The force acting on them is `F=40kg` wt=400N (taking `g=10ms^(-2)`). This force is acting vertically down and hence, normally on the femurs. Thus the average pressure is
`P_(av)=(F)/(A)=2xx10^(5)Nm^(-2)`