Here
`h=10m` and `rho=1000kg` `m^(-3)`. Take `g=10ms^(-2)`
`P=P_(a)+rhogh`
`=1.01xx10^(5)Pa+1000kgm^(-3)xx10ms^(-2)xx10m`
`=2.01xx10^(5)Pa`
`~~2atm`
This is a 100% increase in pressure from surface level. At a depth of 1 km, the increase in pressure is 100 atmm! submarines are designed to withstand such enormous pressures.