Correct Answer - B
Cofficient of performance of refrigerator is `(Q_(2))/W= (T_(2))/(T_(1)-T_(2))`
When the door of a running refrigerator inside a room is left open, `T_(2)rarrT_(1)`. Coefficient of performance increases. `Q_(2)` increases. Therefore, heat energy given to the room increases. Hence the room will be warmed up gradually.