Correct Answer - B
Here, `r=2.5xx10^(-5)m, S=7.28xx10^(-2) N m^(-1)`
Angle of contact , `theta=0^(@), rho=10^(3) kg m^(-3)`
The maximum height to which the sap can rise by capillary action is,
`h=(2Scostheta)/(rrhog)=(2xx7.28xx10^(-2)xxcos0^(@))/(2.5xx10^(-5)xx10^(3)xx9.8)=0.59`m