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The heat absorbed by the system in going through the cyclic process as shown in figure is
image
A. 30.4 J
B. 31.4 J
C. 32.4 J
D. 33.4 J

1 Answer

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Best answer
Correct Answer - B
In a cyclic process heat absorbed by the system is equal to the work done by the system
`therefore` Hence absorbed =work done =area of the given circle
`=pir^(2)=pixx((Delta,P)/(2))((DeltaV)/(2))`
=`3.14xx((200)/(2))xx10^(3)xx((200)/(2))xx10^(-6)`
`=3.14xx100xx10^(3)xx10xx10^(-6)=31.4 J`

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