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The equation of a plane progressive wave travelling along positive direction of `x-`axis is `y=r sin [(2pit)/(T)-(2pix)/(lambda)]` where `y=` displacement of particle at `(x,t),r=` amplitude of vibratio of particle, `T=` time period of wave motion, `lambda=` wavelength of wave ,` x=` starting distance of wave from the origin. Velocity of wave,
`upsilon=vlambda=(lambda)/(T)=` constant.
Acceleration of wave, `a=0`.
Velocity of particle at time `t=(dy)/(dt)`
Acceleration of particle at time `t=(d^(2)y)/(dt^(2))`
A harmonic wave travelling along positive direction of x axis is represented by
`y=0.25xx10^(-3)sin (500t-0.025x)`
where `x` and `y` are in metre and `t` is in second
The amplitude of vibration of particle is
A. `0.25xx10^(-3)cm`
B. `0.25xx10^(-3)m`
C. `500m`
D. `0.025m`

1 Answer

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Best answer
Correct Answer - B
Compare the given equation with the standard form `y=rsin ((2pit)/(T)-(2pix)/(lambda))`
Amplitude of vibration of particle,
`r=0.25xx10^(-3)m`

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